2,304(t)=-16(t)^2

Solution for 2,304(t)=-16(t)^2 equation:

2.304(t)=-16(t)^2

We move all terms to the left:

2.304(t)-(-16(t)^2)=0

determiningTheFunctionDomain
-(-16t^2)+2.304t=0

We get rid of parentheses

16t^2+2.304t=0

a = 16; b = 2.304; c = 0;
Δ = b2-4ac
Δ = 2.3042-4·16·0
Δ = 5.308416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.304)-\sqrt{5.308416}}{2*16}=\frac{-2.304-\sqrt{5.308416}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.304)+\sqrt{5.308416}}{2*16}=\frac{-2.304+\sqrt{5.308416}}{32}
$